Fix errors found by students
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@ -284,7 +284,7 @@
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X \sim \text{Bin}(N,p)
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\end{gather*}
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\begin{gather*}
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P_X(k) = \binom{N}{k} p^k (1-p)^{1-k}
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P_X(k) = \binom{N}{k} p^k (1-p)^{N-k}
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\end{gather*}
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\begin{align*}
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E(X) &= Np\\
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@ -338,7 +338,7 @@
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\begin{greenblock}{Binomialverteilung}
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\vspace*{-6mm}
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\begin{gather*}
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P_X(k) = \binom{N}{k} p^k (1-p)^{1-k}
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P_X(k) = \binom{N}{k} p^k (1-p)^{N-k}
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\end{gather*}
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\begin{align*}
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E(X) &= Np\\
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@ -513,9 +513,9 @@
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\end{gather*}%
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\vspace*{-14mm}%
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\begin{align*}
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P(R = 0) &= P(A = 0 \text{ und } L = 0) &&\hspace{-24mm}= p_A\cdot p_L &&\hspace{-24mm}= 0{,}56 \\
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P(R = 0) &= P(A = 0 \text{ und } L = 0) &&\hspace{-24mm}= p_A\cdot p_L &&\hspace{-24mm}= 0{,}06 \\
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P(R = 1) &= P(A=1 \text{ und } L=0) + P(A=0 \text{ und } L=1) &&\hspace{-24mm}= p_A \cdot (1-p_L) + (1-p_A)\cdot p_L &&\hspace{-24mm}= 0{,}38 \\
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P(R = 2) &= P(A=1 \text{ und } L=1) &&\hspace{-24mm}= (1-p_A)(1-p_L) &&\hspace{-24mm}= 0{,}06
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P(R = 2) &= P(A=1 \text{ und } L=1) &&\hspace{-24mm}= (1-p_A)(1-p_L) &&\hspace{-24mm}= 0{,}56
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\end{align*}
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\vspace*{-10mm}\pause \item Der Autofahrer fährt an $200$ unabhängigen Tagen im Jahr über
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seinen Arbeitsweg zur Arbeit. Wie viele Strafzettel sammelt der
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@ -665,7 +665,7 @@
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\begin{greenblock}{Erzeugende Funktion}
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\vspace*{-6mm}
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\begin{gather*}
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\psi(z) = \sum_{n=1}^{\infty} z^n P(x=n)\\[5mm]
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\psi(z) = \sum_{n=1}^{\infty} z^n P(X=n)\\[5mm]
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P(X=n) = \frac{\psi_X^{(n)}(0)}{n!}
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\end{gather*}
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\end{greenblock}
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