Minor changes in appendix
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@ -89,15 +89,18 @@ problem (\ref{eq:app:sum_reformulated}) becomes%
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In this form, it fits the template for linearized \ac{ADMM}.
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The iterative algorithm can then be expressed as%
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%
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\begin{align*}
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\tilde{\boldsymbol{c}} &\leftarrow \textbf{prox}_{\mu f}\left( \tilde{\boldsymbol{c}}
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- \frac{\mu}{\lambda}\boldsymbol{T}^\text{T}\left( \boldsymbol{T}\tilde{\boldsymbol{c}}
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- \boldsymbol{z} + \boldsymbol{u} \right) \right) \\
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\boldsymbol{z} &\leftarrow \textbf{prox}_{\lambda g}\left(\boldsymbol{T}\tilde{\boldsymbol{c}}
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+ \boldsymbol{u} \right) \\
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\boldsymbol{u} &\leftarrow \boldsymbol{u} + \boldsymbol{T} \tilde{\boldsymbol{c}}
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- \boldsymbol{z}
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.\end{align*}
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\begin{align}
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\begin{aligned}
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\tilde{\boldsymbol{c}} &\leftarrow \textbf{prox}_{\mu f}\left( \tilde{\boldsymbol{c}}
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- \frac{\mu}{\lambda}\boldsymbol{T}^\text{T}\left( \boldsymbol{T}\tilde{\boldsymbol{c}}
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- \boldsymbol{z} + \boldsymbol{u} \right) \right) \\
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\boldsymbol{z} &\leftarrow \textbf{prox}_{\lambda g}\left(\boldsymbol{T}\tilde{\boldsymbol{c}}
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+ \boldsymbol{u} \right) \\
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\boldsymbol{u} &\leftarrow \boldsymbol{u} + \boldsymbol{T} \tilde{\boldsymbol{c}}
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- \boldsymbol{z}.
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\end{aligned}
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\label{eq:app:admm_prox}
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\end{align}
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%
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Using the definition of the proximal operator, the $\tilde{\boldsymbol{c}}$ update step
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@ -134,12 +137,12 @@ can be rewritten to match the definition given in section \ref{sec:dec:LP Decodi
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\boldsymbol{u}_2 \\
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\vdots \\
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\boldsymbol{u}_m
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\end{bmatrix} \right\Vert_2^2 \right)
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\end{bmatrix} \right\Vert_2^2 \right),
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\hspace{5mm}\boldsymbol{z}_j,\boldsymbol{u}_j \in \mathbb{F}_2^{d_j},
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\hspace{2mm} j\in\mathcal{J}\\
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&= \argmin_{\tilde{\boldsymbol{c}}} \left( \boldsymbol{\gamma}^\text{T} \tilde{\boldsymbol{c}}
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- \frac{\mu}{2} \sum_{j \in J} \left\Vert \boldsymbol{T}_j \tilde{\boldsymbol{c}}
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- \boldsymbol{z}_j + \boldsymbol{u}_j \right\Vert_2^2 \right)
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- \frac{\mu}{2} \sum_{j \in J} \left\Vert \boldsymbol{T}_j \tilde{\boldsymbol{c}}
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- \boldsymbol{z}_j + \boldsymbol{u}_j \right\Vert_2^2 \right)
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.\end{align*}
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%
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Step (a) can be justified by observing that multiplication with $\boldsymbol{T}^\text{T}$
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