Fixed most TODOs in decoding techniques section

This commit is contained in:
Andreas Tsouchlos 2023-03-22 14:07:54 +01:00
parent 8cf2e4e6d7
commit ad4dfc6325

View File

@ -196,12 +196,10 @@ of the \acp{LLR} $\gamma_i$ \cite[Sec. 2.5]{feldman_thesis}:%
\hat{\boldsymbol{c}}_{\text{\ac{ML}}} = \argmin_{\boldsymbol{c}\in\mathcal{C}}
\sum_{i=1}^{n} \gamma_i c_i,%
\hspace{5mm} \gamma_i = \ln\left(
\frac{f_{Y_i | C_i} \left( y_i \mid C_i = 0 \right) }
{f_{Y_i | C_i} \left( y_i \mid C_i = 1 \right) } \right)
\frac{f_{Y_i | C_i} \left( y_i \mid c_i = 0 \right) }
{f_{Y_i | C_i} \left( y_i \mid c_i = 1 \right) } \right)
.\end{align*}
%
\todo{$C_i$ or $c_i$?}%
%
The authors propose the following cost function%
\footnote{In this context, \textit{cost function} and \textit{objective function}
have the same meaning.}
@ -209,15 +207,14 @@ for the \ac{LP} decoding problem:%
%
\begin{align*}
g\left( \boldsymbol{c} \right) = \sum_{i=1}^{n} \gamma_i c_i
= \boldsymbol{\gamma}^\text{T}\boldsymbol{c}
.\end{align*}
%
\todo{Write as dot product}
%
With this cost function, the exact integer linear program formulation of \ac{ML}
decoding is the following:%
decoding becomes the following:%
%
\begin{align*}
\text{minimize }\hspace{2mm} &\sum_{i=1}^{n} \gamma_i c_i \\
\text{minimize }\hspace{2mm} & \boldsymbol{\gamma}^\text{T}\boldsymbol{c} \\
\text{subject to }\hspace{2mm} &\boldsymbol{c} \in \mathcal{C}
.\end{align*}%
%
@ -234,13 +231,11 @@ decoding, redefining the constraints in terms of the \text{codeword polytope}
%
\begin{align*}
\text{poly}\left( \mathcal{C} \right) = \left\{
\sum_{\boldsymbol{c} \in \mathcal{C}} \lambda_{\boldsymbol{c}} \boldsymbol{c}
\text{ : } \lambda_{\boldsymbol{c}} \ge 0,
\sum_{\boldsymbol{c} \in \mathcal{C}} \lambda_{\boldsymbol{c}} = 1 \right\}
\sum_{\boldsymbol{c} \in \mathcal{C}} \alpha_{\boldsymbol{c}} \boldsymbol{c}
\text{ : } \alpha_{\boldsymbol{c}} \ge 0,
\sum_{\boldsymbol{c} \in \mathcal{C}} \alpha_{\boldsymbol{c}} = 1 \right\}
,\end{align*} %
%
\todo{$\lambda$ might be confusing here}%
%
which represents the \textit{convex hull} of all possible codewords,
i.e., the convex set of linear combinations of all codewords.
This corresponds to simply lifting the integer requirement.
@ -685,12 +680,11 @@ The resulting formulation of the relaxed optimization problem becomes:%
%
\begin{align}
\begin{aligned}
\text{minimize }\hspace{2mm} &\sum_{i=1}^{n} \gamma_i \tilde{c}_i \\
\text{minimize }\hspace{2mm} & \boldsymbol{\gamma}^\text{T}\tilde{\boldsymbol{c}} \\
\text{subject to }\hspace{2mm} &\boldsymbol{T}_j \tilde{\boldsymbol{c}} \in \mathcal{P}_{d_j}
\hspace{5mm}\forall j\in\mathcal{J}.
\end{aligned} \label{eq:lp:relaxed_formulation}
\end{align}%
\todo{Rewrite sum as dot product}
\todo{Space before $\forall$?}
@ -703,8 +697,7 @@ is a very general one that can be solved with a number of different optimization
In this work \ac{ADMM} is examined, as its distributed nature allows for a very efficient
implementation.
\ac{LP} decoding using \ac{ADMM} can be regarded as a message
passing algorithm with two separate update steps that can be performed
simulatneously;
passing algorithm with separate variable- and check-node update steps;
the resulting algorithm has a striking similarity to \ac{BP} and its computational
complexity has been demonstrated to compare favorably to \ac{BP} \cite{original_admm},
\cite{efficient_lp_dec_admm}.
@ -778,15 +771,25 @@ The steps to solve the dual problem then become:
Luckily, the additional constaints only affect the $\boldsymbol{z}_j$-update steps.
Furthermore, the $\boldsymbol{z}_j$-update steps can be shown to be equivalent to projections
onto the check polytopes $\mathcal{P}_{d_j}$ \cite[Sec. III. B.]{original_admm}
and the $\tilde{\boldsymbol{c}}$-update can be computed analytically \cite[Sec. III.]{lautern}:%
and the $\tilde{\boldsymbol{c}}$-update can be computed analytically%
%
\footnote{In the $\tilde{c}_i$-update rule, the term
$\left( \boldsymbol{z}_j \right)_i$ is a slight abuse of notation, as
$\boldsymbol{z}_j$ has less components than there are variable-nodes $i$.
What is actually meant is the component of $\boldsymbol{z}_j$ that is associated
with the variable node $i$, i.e., $\left( \boldsymbol{T}_j^\text{T}\boldsymbol{z}_j\right)_i$.
The same is true for $\left( \boldsymbol{\lambda}_j \right)_i$.}
%
\cite[Sec. III.]{lautern}:%
%
\begin{alignat*}{3}
\tilde{c}_i &\leftarrow \frac{1}{\left| N_v\left( i \right) \right|} \left(
\sum_{j\in N_v\left( i \right) } \Big( \left( \boldsymbol{\lambda}_j \right)_i
- \left( \boldsymbol{z}_j \right)_i \Big) - \frac{\gamma_i}{\mu} \right)
\sum_{j\in N_v\left( i \right) } \Big( \left( \boldsymbol{z}_j \right)_i
- \frac{1}{\mu} \left( \boldsymbol{\lambda}_j \right)_i \Big)
- \frac{\gamma_i}{\mu} \right)
\hspace{3mm} && \forall i\in\mathcal{I} \\
\boldsymbol{z}_j &\leftarrow \Pi_{\mathcal{P}_{d_j}}\left(
\boldsymbol{T}_j\tilde{\boldsymbol{c}} + \boldsymbol{\lambda}_j \right)
\boldsymbol{T}_j\tilde{\boldsymbol{c}} + \frac{\boldsymbol{\lambda}_j}{\mu} \right)
\hspace{3mm} && \forall j\in\mathcal{J} \\
\boldsymbol{\lambda}_j &\leftarrow \boldsymbol{\lambda}_j
+ \mu\left( \boldsymbol{T}_j\tilde{\boldsymbol{c}}
@ -794,9 +797,7 @@ and the $\tilde{\boldsymbol{c}}$-update can be computed analytically \cite[Sec.
\hspace{3mm} && \forall j\in\mathcal{J}
.\end{alignat*}
%
\todo{$\tilde{c}_i$-update With or without projection onto $\left[ 0, 1 \right] ^n$?}
%
One thing to note is that all of the $\boldsymbol{z}_j$-updates can be computed simultaneously,
It should be noted that all of the $\boldsymbol{z}_j$-updates can be computed simultaneously,
as they are independent of one another.
The same is true for the updates of the individual components of $\tilde{\boldsymbol{c}}$.
@ -809,13 +810,7 @@ Effectively, all of the $\left|\mathcal{J}\right|$ parity constraints are
able to be handled at the same time.
This can also be understood by interpreting the decoding process as a message-passing
algorithm \cite[Sec. III. D.]{original_admm}, \cite[Sec. II. B.]{efficient_lp_dec_admm},
as is shown in figure \ref{fig:lp:message_passing}
\footnote{$\epsilon_{\text{pri}} > 0$ and $\epsilon_{\text{dual}} > 0$ are additional parameters
defining the tolerances for the stopping criteria of the algorithm.
The variable $\boldsymbol{z}_j^\prime$ denotes the value of
$\boldsymbol{z}_j$ in the previous iteration.}%
\todo{Move footnote to figure caption}%
.%
as is shown in figure \ref{fig:lp:message_passing}.%
\todo{Explicitly specify sections?}%
%
\begin{figure}[H]
@ -828,26 +823,35 @@ Initialize $\tilde{\boldsymbol{c}}, \boldsymbol{z}_{[1:m]}$ and $\boldsymbol{\la
while $\sum_{j\in\mathcal{J}} \lVert \boldsymbol{T}_j\tilde{\boldsymbol{c}} - \boldsymbol{z}_j \rVert_2 \ge \epsilon_{\text{pri}}$ or $\sum_{j\in\mathcal{J}} \lVert \boldsymbol{z}^\prime_j - \boldsymbol{z}_j \rVert_2 \ge \epsilon_{\text{dual}}$ do
for all $j$ in $\mathcal{J}$ do
$\boldsymbol{z}_j \leftarrow \Pi_{\mathcal{P}_{d_j}}\left(
\boldsymbol{T}_j\tilde{\boldsymbol{c}} + \boldsymbol{\lambda}_j \right)$
$\boldsymbol{\lambda}_j \leftarrow \boldsymbol{\lambda}_j
\boldsymbol{T}_j\tilde{\boldsymbol{c}} + \frac{\boldsymbol{\lambda}_j}{\mu} \right)$
$\boldsymbol{\lambda}_j \leftarrow \boldsymbol{\lambda}_j
+ \mu\left( \boldsymbol{T}_j\tilde{\boldsymbol{c}}
- \boldsymbol{z}_j \right)$
end for
for all $i$ in $\mathcal{I}$ do
$\tilde{c}_i \leftarrow \frac{1}{\left| N_v\left( i \right) \right|} \left(
\sum_{j\in N_v\left( i \right) } \Big( \left( \boldsymbol{\lambda}_j \right)_i
- \left( \boldsymbol{z}_j \right)_i \Big) - \frac{\gamma_i}{\mu} \right)$
\sum_{j\in N_v\left( i \right) } \Big(
\left( \boldsymbol{z}_j \right)_i - \frac{1}{\mu} \left( \boldsymbol{\lambda}_j
\right)_i
\Big) - \frac{\gamma_i}{\mu} \right)$
end for
end while
\end{genericAlgorithm}
\caption{\ac{LP} decoding using \ac{ADMM} interpreted as a message passing algorithm}
\caption{\ac{LP} decoding using \ac{ADMM} interpreted as a message passing algorithm%
\protect\footnotemark{}}
\label{fig:lp:message_passing}
\end{figure}%
%
\noindent The $\tilde{c}_i$-updates can be understood as a variable-node update step,
and the $\boldsymbol{z}_j$- and $\boldsymbol{\lambda}_j$-updates can be understood as
a check-node update step.
\footnotetext{$\epsilon_{\text{pri}} > 0$ and $\epsilon_{\text{dual}} > 0$
are additional parameters
defining the tolerances for the stopping criteria of the algorithm.
The variable $\boldsymbol{z}_j^\prime$ denotes the value of
$\boldsymbol{z}_j$ in the previous iteration.}%
%
\noindent The $\boldsymbol{z}_j$- and $\boldsymbol{\lambda}_j$-updates can be understood as
a check-node update step (lines $3$-$6$) and the $\tilde{c}_i$-updates can be understood as
a variable-node update step (lines $7$-$9$ in figure \ref{fig:lp:message_passing}).
The updates for each variable- and check-node can be perfomed in parallel.
With this interpretation it becomes clear why \ac{LP} decoding using \ac{ADMM}
is able to achieve similar computational complexity to \ac{BP}.
@ -948,17 +952,13 @@ $L \left( \boldsymbol{y} \mid \tilde{\boldsymbol{x}} \right) = -\ln\left(
%
\begin{align*}
\hat{\boldsymbol{x}} &= \argmax_{\tilde{\boldsymbol{x}} \in \mathbb{R}^{n}}
\mathrm{e}^{- L\left( \boldsymbol{y} \mid \tilde{\boldsymbol{x}} \right) }
\mathrm{e}^{-\gamma h\left( \tilde{\boldsymbol{x}} \right) } \\
&= \argmin_{\tilde{\boldsymbol{x}} \in \mathbb{R}^n} \left(
L\left( \boldsymbol{y} \mid \tilde{\boldsymbol{x}} \right)
+ \gamma h\left( \tilde{\boldsymbol{x}} \right)
\right)%
\mathrm{e}^{- L\left( \boldsymbol{y} \mid \tilde{\boldsymbol{x}} \right) }
\mathrm{e}^{-\gamma h\left( \tilde{\boldsymbol{x}} \right) } \\
&= \argmin_{\tilde{\boldsymbol{x}} \in \mathbb{R}^n} \big(
L\left( \boldsymbol{y} \mid \tilde{\boldsymbol{x}} \right)
+ \gamma h\left( \tilde{\boldsymbol{x}} \right)
\big)%
.\end{align*}%
\todo{\textbackslash left($\cdot$ \textbackslash right)\\
$\rightarrow$\\
\textbackslash big( $\cdot$ \textbackslash big)\\
?}%
%
Thus, with proximal decoding, the objective function
$g\left( \tilde{\boldsymbol{x}} \right)$ considered is%
@ -1011,7 +1011,6 @@ It is then immediately approximated with gradient-descent:%
\hspace{5mm} \gamma > 0, \text{ small}
.\end{align*}%
%
\todo{explicitly state $\nabla h$?}
The second step thus becomes%
%
\begin{align*}