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Correct Algorithm 1

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Andreas Tsouchlos 2024-01-07 22:27:36 +01:00
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commit ad354f8f02
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letter.tex
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@ -8,6 +8,7 @@
\usepackage{siunitx}
\usepackage{dsfont}
\usepackage{mleftright}
\usepackage{bbm}
\usepackage{tikz}
\usetikzlibrary{spy, arrows.meta,arrows}
@ -303,7 +304,7 @@ The resulting decoding process as described in \cite{proximal_paper} is
presented in Algorithm \ref{alg:proximal_decoding}.
\begin{algorithm}
\caption{Proximal decoding algorithm for an AWGN channel.}
\caption{Proximal decoding algorithm for an AWGN channel \cite{proximal_paper}.}
\label{alg:proximal_decoding}
\begin{algorithmic}
@ -311,7 +312,7 @@ presented in Algorithm \ref{alg:proximal_decoding}.
\STATE \textbf{for} $K$ iterations \textbf{do}
\STATE \hspace{5mm} $\boldsymbol{r} \leftarrow \boldsymbol{s} - \omega \left( \boldsymbol{s} - \boldsymbol{y} \right) $
\STATE \hspace{5mm} $\boldsymbol{s} \leftarrow \Pi_\eta \left(\boldsymbol{r} - \gamma \nabla h\left( \boldsymbol{r} \right) \right)$
\STATE \hspace{5mm} $\boldsymbol{\hat{c}} \leftarrow \mathds{1} \left\{ \text{sign}\left( \boldsymbol{s} \right) = -1 \right\}$
\STATE \hspace{5mm} $\boldsymbol{\hat{c}} \leftarrow \mathbbm{1}_{\left\{ \boldsymbol{s} \preceq 0 \right\}}$
\STATE \hspace{5mm} \textbf{if} $\boldsymbol{H}\boldsymbol{\hat{c}} = \boldsymbol{0}$ \textbf{do}
\STATE \hspace{10mm} \textbf{return} $\boldsymbol{\hat{c}}$
\STATE \hspace{5mm} \textbf{end if}